Rozwiązanie:

Obliczamy:

$\frac{F_{\text{d.r}}}{F_{\text{g}}}=\frac{4\cdot 3,14^2\cdot {\left(3,39\cdot 10^6\mathrm{m}\right)}^3}{6,67\cdot 10^{-11}\mathrm{N}\cdot \frac{{\mathrm{m}}^2}{\mathrm{k}{\mathrm{g}}^2}\cdot 6,4\cdot 10^{23}\mathrm{kg}\cdot {\left(8,862\cdot 10^4\mathrm{s}\right)}^2}=$

$=\frac{39,4384\cdot 38,958219\cdot 10^{18}{\mathrm{m}}^3}{42,688\cdot 10^{12}\mathrm{kg}\cdot \frac{\mathrm{m}}{{\mathrm{s}}^2}\cdot \frac{{\mathrm{m}}^2}{\mathrm{kg}}\cdot 78,535044\cdot 10^8{\mathrm{s}}^2}\approx$

$\approx \frac{1536,4498\cdot 10^{18}}{3352,504\cdot 10^{20}}\approx$

$\approx 0,4583\cdot 10^{-2}=$

$=0,004583$