$\begin{array}{lll}{a}_1=\frac{-8-16}{2}<0& & \\ & \Rightarrow & a=4\\ a_2=\frac{-8+16}{2}=\frac{8}{2}=4& & \end{array}$

Zdanie pierwsze

$h=4\sqrt{3}$

$2a=2\cdot 4=8\ne h$

Zdanie drugie

$P_b=6\cdot \frac{1}{2}ah=6\cdot \frac{1}{2}\cdot 4\cdot 4\sqrt{3}=48\sqrt{3}$

$P_p=6\cdot \frac{a^2\sqrt{3}}{4}=6\cdot \frac{4^2\sqrt{3}}{4}=6\cdot \frac{16\sqrt{3}}{4}=24\sqrt{3}$

$\frac{P_b}{P_p}=\frac{48\sqrt{3}}{24\sqrt{3}}=\frac{48}{24}=\frac{2}{1}=2:1$