`(-2)^(-5)=(-1/2)^5=-1/32

`(-1/2)^(-9)=(-2)^9

${\left(-\frac{3}{4}\right)}^{-2}={\left(-\frac{4}{3}\right)}^2=\frac{16}{9}=$

${\left(-\frac{3}{4}\right)}^{-2}={\left(-\frac{4}{3}\right)}^2=\frac{16}{9}=$ $1\frac{7}{9}>\left(\frac{3}{4}\right)\cdot \left(-2\right)=-\frac{3}{2}=-1\frac{1}{2}$

`(-2)^(-4)=(-1/2)^4=1/16

${\left(0,2\right)}^{-1}=\frac{10}{2}=5>\left(-1\right)\cdot 0,2=-0,2$

${\left(1\frac{1}{2}\right)}^{-2}={\left(\frac{3}{2}\right)}^{-2}={\left(\frac{2}{3}\right)}^2=$ $\frac{4}{9}>\left(-2\right)\cdot 1\frac{1}{2}=\left(-2\right)\cdot \frac{3}{2}=-3$

$2^{-4}+1^{-1}={\left(\frac{1}{2}\right)}^4+1=\frac{1}{16}+1=$ $1\frac{1}{16}>{\left(-1\right)}^{-1}+4^{-2}=-1+{\left(\frac{1}{4}\right)}^2=-1+\frac{1}{16}=-\frac{15}{16}$

${\left(-9\right)}^{-1}\cdot {\left(\frac{1}{3}\right)}^{-2}=\left(-\frac{1}{9}\right)\cdot 3^2=\left(-\frac{1}{9}\right)\cdot 9=$ $-1>-{\left(-0,5\right)}^{-2}=-{\left(-2\right)}^2=-4$