$a)\frac{7}{\sqrt{2}}=\frac{7}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{7\cdot \sqrt{2}}{\sqrt{2}\cdot \sqrt{2}}=\frac{7\sqrt{2}}{\sqrt{4}}=\frac{7\sqrt{2}}{2}=3\frac{1}{2}\sqrt{2}$  

$b)\frac{6}{\sqrt{3}}=\frac{6}{\sqrt{\cdot }}\frac{\sqrt{3}}{\sqrt{3}}=\frac{6\sqrt{3}}{\sqrt{9}}=\frac{{\sout{6}}^2\sqrt{3}}{{\sout{3}}^1}=2\sqrt{3}$  

$c)\frac{5}{\sqrt{10}}=\frac{5}{\sqrt{\cdot }}\frac{\sqrt{10}}{\sqrt{10}}=\frac{5\sqrt{10}}{\sqrt{10}\cdot \sqrt{10}}=\frac{5\sqrt{10}}{\sqrt{100}}=\frac{{\sout{5}}^1\sqrt{10}}{{\sout{10}}^2}=\frac{\sqrt{10}}{2}$ $c)\frac{5}{\sqrt{10}}=\frac{5}{\sqrt{\cdot }}\frac{\sqrt{10}}{\sqrt{10}}=\frac{5\sqrt{10}}{\sqrt{10}\cdot \sqrt{10}}=\frac{5\sqrt{10}}{\sqrt{100}}=\frac{{\sout{5}}^1\sqrt{10}}{{\sout{10}}^2}=\frac{\sqrt{10}}{2}$  

$d)\frac{6}{\sqrt{6}}=\frac{6}{\sqrt{6}}=\frac{6}{\sqrt{6}}\cdot \frac{\sqrt{6}}{\sqrt{6}}=\frac{6\cdot \sqrt{6}}{\sqrt{6}\cdot \sqrt{6}}=\frac{6\sqrt{6}}{\sqrt{36}}=\frac{6\sqrt{6}}{6}=\sqrt{6}$  

$e)\frac{17}{\sqrt{17}}=\frac{17}{\sqrt{17}}\cdot \frac{\sqrt{17}}{\sqrt{17}}=\frac{17\cdot \sqrt{17}}{\sqrt{17}\cdot \sqrt{17}}=\frac{17\sqrt{17}}{17}=\sqrt{17}$  

$f)\frac{7}{2\sqrt{14}}=\frac{7}{2\sqrt{14}}\cdot \frac{\sqrt{14}}{\sqrt{14}}=\frac{7\cdot \sqrt{14}}{2\sqrt{14}\cdot \sqrt{14}}=\frac{7\sqrt{14}}{2\sqrt{{14}^2}}=\frac{{\sout{7}}^1\sqrt{14}}{2\cdot {\sout{14}}^2}=\frac{\sqrt{14}}{4}$  

$g)\frac{3}{2\sqrt{6}}=\frac{3}{2\sqrt{6}}\cdot \frac{\sqrt{6}}{\sqrt{6}}=\frac{3\cdot \sqrt{6}}{2\sqrt{6}\cdot \sqrt{6}}=\frac{3\sqrt{6}}{2\sqrt{6^2}}=\frac{3\sqrt{6}}{2\cdot 6}=\frac{{\sout{3}}^1\sqrt{6}}{{\sout{12}}^4}=\frac{\sqrt{6}}{4}$  

$h)\frac{\sqrt{7}}{\sqrt{5}}=\frac{\sqrt{7}}{\sqrt{5}}\cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{7}\cdot \sqrt{5}}{\sqrt{5^2}}=\frac{\sqrt{35}}{\sqrt{25}}=\frac{\sqrt{35}}{5}$  

$i)\frac{\sqrt{15}}{\sqrt{6}}=\sqrt{\frac{15}{6}}=\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}=\frac{\sqrt{5}}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{5}\cdot \sqrt{2}}{\sqrt{2}\cdot \sqrt{2}}=\frac{\sqrt{10}}{\sqrt{4}}=\frac{\sqrt{10}}{2}$  

$j)\frac{-\sqrt{11}}{\sqrt{2}}=\frac{-\sqrt{11}}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{-\sqrt{11}\cdot \sqrt{2}}{\sqrt{2^2}}=\frac{-\sqrt{22}}{2}$  

$k)\frac{-\sqrt{14}}{\sqrt{21}}=-\sqrt{\frac{14}{21}}=-\sqrt{\frac{2}{3}}==-\frac{\sqrt{2}}{\sqrt{3}}=-\frac{\sqrt{2}}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}=\frac{-\sqrt{2}\cdot \sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}=\frac{-\sqrt{6}}{\sqrt{9}}=-\frac{\sqrt{6}}{3}$      

$l)\sqrt{3\frac{2}{5}}=\sqrt{\frac{17}{5}}=\frac{\sqrt{17}}{\sqrt{5}}=\frac{\sqrt{17}}{\sqrt{5}}\cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{17}\cdot \sqrt{5}}{\sqrt{5}\cdot \sqrt{5}}=\frac{\sqrt{85}}{\sqrt{25}}=\frac{\sqrt{85}}{5}$