$a)p=4\frac{2}{5}:\left(\frac{7}{15}-\frac{1}{10}\right)=\frac{22}{5}:\left(\frac{14}{30}-\frac{3}{30}\right)=\frac{22}{5}:\frac{11}{30}=\frac{{\sout{22}}^2}{5}\cdot \frac{30}{{\sout{11}}^1}=$   $\frac{60}{5}=12$  

Największa liczba całkowita mniejsza od p to 11 

$b)p=1\frac{3}{8}:\left(\frac{5}{4}-\frac{7}{6}\right)=\frac{11}{8}:\left(\frac{15}{12}-\frac{14}{12}\right)=\frac{11}{8}:\frac{1}{12}=\frac{11}{{\sout{8}}^2}\cdot \frac{{\sout{12}}^3}{1}=\frac{33}{2}=16\frac{1}{2}$