7 szkoły podstawowej

8 szkoły podstawowej

Chemia w zadaniach i przykładach. Zbiór zadań dla klas 7 i 8 szkoły podstawowej.

Chemia

Chemia 7

Chemia 7 i 8

Chemia Nowej Ery 7

Ciekawa chemia 7

Świat chemii 7

Dane :&nbsp; T=20℃ &nbsp; mr​=800 g &nbsp;&nbsp; mw​=200 g &nbsp; Szukane :&nbsp;

Dane :&nbsp; Cp1​=63% Cp2​=10% Cp​=30% Szukane :&nbsp;

a) Dane: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/69e7039713684a84eafdc581d25d65b6d2eea8ef50e885fc1075beb5b03b16a5_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/69e7039713684a84eafdc581d25d65b6d2eea8ef50e885fc1075beb5b03b16a5_big.svg" type="image/svg+xml"></object> &nbsp; Wiemy, że rozpuszczalność azotanu(V) sodu w 30oC wynosi 96 g substancji na 100 g wody, tak więc masa roztworu wynosi: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/c9a38950b99336b504f54c8cede3b5fb7943fb878b7138284f8dfe424228e871_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/c9a38950b99336b504f54c8cede3b5fb7943fb878b7138284f8dfe424228e871_big.svg" type="image/svg+xml"></object> &nbsp; Aby obliczyć ile gramów soli zawiera 250 g roztworu układamy proporcję: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/14d728282b7ad3b20f231a22d34ab064054f39fa7d79ca873152e8f97b76b536_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/14d728282b7ad3b20f231a22d34ab064054f39fa7d79ca873152e8f97b76b536_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp;&nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/7ba3e183c80c6dca9a153cee9e99d53857ae4b12d77581bc2c4db35a2f3efa69_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/7ba3e183c80c6dca9a153cee9e99d53857ae4b12d77581bc2c4db35a2f3efa69_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/134d0123a4a9f8d4a0014b6491ae2a946899218ab06ae78a8c12eab2f03528b9_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/134d0123a4a9f8d4a0014b6491ae2a946899218ab06ae78a8c12eab2f03528b9_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/b4e6b5788db051e9a9773017998e010cffd00fcb1eacba836b6bb3a058ee1f9d_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/b4e6b5788db051e9a9773017998e010cffd00fcb1eacba836b6bb3a058ee1f9d_big.svg" type="image/svg+xml"></object> tyle g azotanu(V) sodu jest w 250 g roztworu. Obliczamy masę wody w roztworze: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/8e78817af55d9f5ec5bae59606bfc07789d3e38ae51a60984da2441946982d31_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/8e78817af55d9f5ec5bae59606bfc07789d3e38ae51a60984da2441946982d31_big.svg" type="image/svg+xml"></object> &nbsp; Odpowiedź: Roztwór zawiera 122,4 g azotanu(V) sodu oraz 127,6 g wody. b) Należy rozpuścić 122,4 g azotanu(V) amonu w 127,6 g wody przy założeniu, że gęstość wody wynosi 1 g/cm3 to w 127,6 cm3 wody.&nbsp; c) Dane: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/669f9b433518e2a5752798f35d7d5738372b750314a79cb09bc27f1bc1e0f4c2_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/669f9b433518e2a5752798f35d7d5738372b750314a79cb09bc27f1bc1e0f4c2_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/69e7039713684a84eafdc581d25d65b6d2eea8ef50e885fc1075beb5b03b16a5_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/69e7039713684a84eafdc581d25d65b6d2eea8ef50e885fc1075beb5b03b16a5_big.svg" type="image/svg+xml"></object> &nbsp; Szukane: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/2a6879650f3ddbac71f6f4c5aabb4bb1e9a143505f6410df92ff44fcfe951e5d_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/2a6879650f3ddbac71f6f4c5aabb4bb1e9a143505f6410df92ff44fcfe951e5d_big.svg" type="image/svg+xml"></object> &nbsp; Rozwiązanie: Korzystamy ze wzoru na stężenie procentowe: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/b1e02aeb1791c430e2157794ed8c54fb3a3415e30534b55bcdafd27609d48e19_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/b1e02aeb1791c430e2157794ed8c54fb3a3415e30534b55bcdafd27609d48e19_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/304279d57fab570fe0d4b7caa701b0d698241f20dcd330d51bdccb881f8b9e62_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/304279d57fab570fe0d4b7caa701b0d698241f20dcd330d51bdccb881f8b9e62_big.svg" type="image/svg+xml"></object> &nbsp; Odpowiedź: Stężenie procentowe otrzymanego roztworu wynosi 49%. &nbsp;

Dane :&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/a2beed141b572ba55c2d89289c55754945b9d8d718c8df832d8c5ae9dffea944_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/a2beed141b572ba55c2d89289c55754945b9d8d718c8df832d8c5ae9dffea944_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/bf0734308869eb23a78fddaad278f708f1f7e94647d54acdbcc7ed7d211abbea_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/bf0734308869eb23a78fddaad278f708f1f7e94647d54acdbcc7ed7d211abbea_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/f3d384e55f19ad6aeb3c0412663838a425b64cf2ffd0521acc7b0e9b5bf3d195_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/f3d384e55f19ad6aeb3c0412663838a425b64cf2ffd0521acc7b0e9b5bf3d195_big.svg" type="image/svg+xml"></object> &nbsp; Szukane :&nbsp;

Dane :&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/627981bfc88a9f4fbb80ea6f0b3c3032a2801aaf4a82804afff02e6a195dc6e2_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/627981bfc88a9f4fbb80ea6f0b3c3032a2801aaf4a82804afff02e6a195dc6e2_big.svg" type="image/svg+xml"></object> <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/2bddcc02c54b3fb2606b7eae419450428a9da17ee1846a788e5f9e7b569e9e6a_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/2bddcc02c54b3fb2606b7eae419450428a9da17ee1846a788e5f9e7b569e9e6a_big.svg" type="image/svg+xml"></object> <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/21c9fdb0d4e1a4d4c3984734d2183a77dfae3c8c7089339ee20804032272bbe9_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/21c9fdb0d4e1a4d4c3984734d2183a77dfae3c8c7089339ee20804032272bbe9_big.svg" type="image/svg+xml"></object> Szukane :&nbsp;

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