$2x-3\left(-3x-1\right)=4-x-1$

$2x+9x+3=-x+3$

$12x=0$

$x=0$

$b)\frac{2}{3}\left(3x-1\right)-\frac{3}{2}\left[2x+3\left(x-2\right)\right]=1$

$4\left(3x-1\right)-9\left(5x-6\right)=6$

$12x-4-45x+54=6$

$33x=44$

$x=\frac{44}{33}$  

$x=1\frac{1}{3}$