$\text{a)}{S}_x\left(P\right)=P{}^{\prime },S_x\left(\begin{array}{c}-3\text{,}4\end{array}\right)=\left(-3,-4\right),\text{czyli}P{}^{\prime }=\left(-3,-4\right)$       

$S_y\left(P\right)=P{}^{\prime \prime },S_y\left(\begin{array}{c}-3\text{,}4\end{array}\right)=\left(3,4\right),\text{czyli}P{}^{\prime \prime }=\left(3,4\right)$   

 

$\text{b)}{S}_x\left(P\right)=P{}^{\prime },S_x\left(\begin{array}{c}x\text{,}y\end{array}\right)=\left(2,-3\right),\text{czyli}P=\left(2,3\right)$  

Uwaga!!! W odpowiedzi zamiast P' powinno być napisane P. 

$S_y\left(P\right)=P{}^{\prime \prime },S_y\left(\begin{array}{c}2\text{,}3\end{array}\right)=\left(-2,3\right),\text{czyli}P{}^{\prime \prime }=\left(-2,3\right)$   

 

$\text{c)}{S}_y\left(P\right)=P{}^{\prime \prime },S_y\left(\begin{array}{c}x\text{,}y\end{array}\right)=\left(-2,0\right),\text{czyli}P=\left(2,0\right)$  

$S_x\left(P\right)=P{}^{\prime },S_x\left(\begin{array}{c}2\text{,}0\end{array}\right)=\left(2,0\right),\text{czyli}P{}^{\prime }=\left(2,0\right)$        

 

$\text{d)}{S}_x\left(P\right)=P{}^{\prime },S_x\left(\begin{array}{c}0\text{,}0\end{array}\right)=\left(0,0\right),\text{czyli}P{}^{\prime }=\left(0,0\right)$  

$S_y\left(P\right)=P{}^{\prime \prime },S_y\left(\begin{array}{c}0\text{,}0\end{array}\right)=\left(0,0\right),\text{czyli}P{}^{\prime \prime }=\left(0,0\right)$