${\left(-\frac{1}{4}\right)}^0=1$

$\sqrt[3]{27}=3$

$-4^2=-16$

$-\sqrt{1,21}=-1,1$

${\left(-\frac{1}{3}\right)}^2=\frac{1}{9}$

${\left(-4\right)}^2=16$

$-{\left(\frac{1}{2}\right)}^2=-\frac{1}{4}$

 

$-4^2<-\sqrt{1,21}<-{\left(\frac{1}{2}\right)}^2<{\left(-\frac{1}{4}\right)}^0<\sqrt[3]{27}<{\left(-4\right)}^2$