III gimnazjum

Matematyka 2001

Matematyka

Liczy się matematyka 3

Matematyka 2001. Zeszyt ćwiczeń cz. 1

Matematyka 2001. Zeszyt ćwiczeń cz. 2

Matematyka 3. Ćwiczenia podstawowe

Matematyka 3. Zeszyt zadań

Matematyka na czasie! 3

Matematyka wokół nas 3

Matematyka wokół nas 3. Zeszyt ćwiczeń cz. 1

Matematyka wokół nas 3. Zeszyt ćwiczeń cz. 2

Matematyka z plusem 3

Matematyka z plusem 3. Zbiór zadań 2001

Policzmy to razem 3

Rysunek pomocniczy: <img src="https://odrabiamy.pl/uploads/exercise_photo/image/104925/zad5s127.jpg" width="347" height="225"> Korzystając z&nbsp; twierdzenia Pitagorasa wiemy, że: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/230509da6fa927a467d209a8f553141d12a5032144736c1e81102d18f4d3d130_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/230509da6fa927a467d209a8f553141d12a5032144736c1e81102d18f4d3d130_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/ed80666a59f344835fec777bf17671bd6062a28c5940e9f62505cece15a96399_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/ed80666a59f344835fec777bf17671bd6062a28c5940e9f62505cece15a96399_big.svg" type="image/svg+xml"></object> &nbsp; zatem: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/fd0a4cedfbb06a042a72b22e254a008a3238593bd5c34e049adcfff7c92c431a_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/fd0a4cedfbb06a042a72b22e254a008a3238593bd5c34e049adcfff7c92c431a_big.svg" type="image/svg+xml"></object> &nbsp; oraz <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/20694dcb33522c96b95325bec3a65f5450242abca72f1b81da0376a36a56927c_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/20694dcb33522c96b95325bec3a65f5450242abca72f1b81da0376a36a56927c_big.svg" type="image/svg+xml"></object> &nbsp; więc: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/e22bb53c3d430c9c0fe87848f95ad7e5734d509827a0db417176d497467505ec_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/e22bb53c3d430c9c0fe87848f95ad7e5734d509827a0db417176d497467505ec_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/1388a9b64c2062f3a75946da1682523230d79a326bf6c123f6fa8d4bd9a2604d_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/1388a9b64c2062f3a75946da1682523230d79a326bf6c123f6fa8d4bd9a2604d_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/233380df374cf84e8622808d001a3eed2db21571888fcc0c2677563051d03e07_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/233380df374cf84e8622808d001a3eed2db21571888fcc0c2677563051d03e07_big.svg" type="image/svg+xml"></object> &nbsp;

Rysunek pomocniczy: <img class="img-responsive img-thumbnail dropzone-img" src="https://odrabiamy.pl//uploads/exercise_photo/image/104927/zad6s127.jpg" width="425" height="238"> Korzystając z twierdzenia Pitagorasa obliczmy długość boku oznaczonego literą x: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/a573bbe5d86be0fd0db258c3ea94b074bf4f59051a3b5291aa74b87567e2fa9d_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/a573bbe5d86be0fd0db258c3ea94b074bf4f59051a3b5291aa74b87567e2fa9d_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/a2c1144398e7228264a9a05b30093fa11832a01c3a21e9e2741e227bceea3081_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/a2c1144398e7228264a9a05b30093fa11832a01c3a21e9e2741e227bceea3081_big.svg" type="image/svg+xml"></object>

Rysunek pomocniczy: <img class="img-responsive img-thumbnail dropzone-img" src="https://odrabiamy.pl//uploads/exercise_photo/image/105227/zad7s127.jpg" width="231" height="251"> Wiemy, że odcinki&nbsp;AD&nbsp;i&nbsp;DC&nbsp;oraz&nbsp;AD&nbsp;i&nbsp;BD&nbsp;są równej długości trójkąty ADC&nbsp; i ABD są prostokątne i równoramienne

Rysunek pomocniczy: <img class="img-responsive img-thumbnail dropzone-img" src="https://odrabiamy.pl//uploads/exercise_photo/image/105225/zad8s127.jpg" width="526" height="395"> Wiemy, że: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/586b9ebeb1716b0a613280de2bfdbd96b2cf47ff1239e1a9aa5001709e9cc4b2_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/586b9ebeb1716b0a613280de2bfdbd96b2cf47ff1239e1a9aa5001709e9cc4b2_big.svg" type="image/svg+xml"></object> &nbsp; Sprawdźmy czy: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/cda591c0e478250ad6aadac3985db8b557edb30d483a33be3775309a82061318_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/cda591c0e478250ad6aadac3985db8b557edb30d483a33be3775309a82061318_big.svg" type="image/svg+xml"></object> &nbsp;

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