∙	$x+1$	$3-x$	$4-x$
$3+x$	$x^2+4x+3$	$-x^2+9$	$-x^2+x+12$
$6-x$	$-x^2+5x+6$	$x^2-9x+18$	$x^2-10x+24$
$-x-7$	$-x^2-8x-7$	$x^2+4x-21$	$x^2+3x-28$

Obliczenia:

$\left(3+x\right)\cdot \left(x+1\right)=3\cdot x+3\cdot 1+x\cdot x+x\cdot 1=3x+3+x^2+x=x^2+4x+3$

$\left(3+x\right)\cdot \left(3-x\right)=3\cdot 3+3\cdot \left(-x\right)+x\cdot 3+x\cdot \left(-x\right)=9-3x+3x-x^2=-x^2+9$

$\left(3+x\right)\cdot \left(4-x\right)=3\cdot 4+3\cdot \left(-x\right)+x\cdot 4+x\cdot \left(-x\right)=12-3x+4x-x^2=-x^2+x+12$

$\left(6-x\right)\cdot \left(x+1\right)=6\cdot x+6\cdot 1-x\cdot x-x\cdot 1=6x+6-x^2-x=-x^2+5x+6$

$\left(6-x\right)\cdot \left(3-x\right)=6\cdot 3+6\cdot \left(-x\right)-x\cdot 3-x\cdot \left(-x\right)=18-6x-3x+x^2=x^2-9x+18$

$\left(6-x\right)\cdot \left(4-x\right)=6\cdot 4+6\cdot \left(-x\right)-x\cdot 4-x\cdot \left(-x\right)=24-6x-4x+x^2=x^2-10x+24$

$\left(-x-7\right)\cdot \left(x+1\right)=-x\cdot x-x\cdot 1-7\cdot x-7\cdot 1=-x^2-x-7x-7=-x^2-8x-7$

$\left(-x-7\right)\cdot \left(3-x\right)=-x\cdot 3-x\cdot \left(-x\right)-7\cdot 3-7\cdot \left(-x\right)=-3x+x^2-21+7x=x^2+4x-21$

$\left(-x-7\right)\cdot \left(4-x\right)=-x\cdot 4-x\cdot \left(-x\right)-7\cdot 4-7\cdot \left(-x\right)=-4x+x^2-28+7x=x^2+3x-28$