$5\frac{2}{5}-3,2\cdot 1\frac{1}{2}=5\frac{2}{5}-\frac{{\sout{32}}^{16}}{10}\cdot \frac{3}{{\sout{2}}^1}=5\frac{2}{5}-\frac{48}{10}=5\frac{2}{5}-\frac{24}{5}=\frac{27}{5}-\frac{24}{5}=\frac{3}{5}$