14
15
1
2
3
4
a) f(x)=∣tgx∣+1
Df={2kπ}, k∈C
b) f(x)=∣∣tg(x+2π)∣∣
Df={kπ), k∈C
c) f(x)=−2∣∣tg(x−4π)∣∣
Df={−4π+kπ}, k∈C
Komentarze