I gimnazjum

Matematyka na czasie! 1

Każda liczba różna od zera podniesiona do potęgi 0 jest równa 1

42=16 52=25

a=73−33=343−27=316 b=92−52=81−25=56

Zgodnie z własnościami potęgowania upraszczamy wyrażenie:

I. Sprawdźmy, jaka jest ostatnia cyfra kolejnych potęg liczby 7. 70=1 71=7

a) 3625​<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='2.48em' viewBox='0 0 400000 2592' preserveAspectRatio='xMinYMin slice'><path d='M424,2478
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l0 -0c4,-6.7,10,-10,18,-10 H400000
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M834 80h400000v40h-400000z'/></svg>​25<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
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c69,-144,104.5,-217.7,106.5,-221
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c5.3,-9.3,12,-14,20,-14
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c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​​=65​

a) 12m2−12⋅1m⋅1m=12⋅100cm⋅100cm=12⋅10000cm2=120000cm2

Sprowadźmy wielkości do tej samej jednostki. 100kg=100⋅1kg=100⋅1000g=100 000g

a) 1km=1000m=1000⋅1m=1000⋅100cm=100000cm=105cm

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