$a)6x-\left(10-2x\right)=3x+5$

$6x-10+2x=3x+5\mid +10$

$8x=3x+15\mid -3x$

$5x=15\mid :5$

$x=3$

$b)8-\left(4x-12\right)=8x-\left(3x-2\right)$

$8-4x+12=8x-3x+2$

$20-4x=5x+2\mid -20$

$-4x=5x-18\mid -5x$

$-9x=-18\mid :\left(-9\right)$

$x=2$

 

$c)\frac{3}{4}\left(x-5\right)+x=x$

$\frac{3}{4}x-\frac{15}{4}+x=x\mid -x$

$\frac{3}{4}x-\frac{15}{4}=0\mid +\frac{15}{4}$

$\frac{3}{4}x=\frac{15}{4}\mid :\frac{3}{4}$

$x=\frac{15}{4}:\frac{3}{4}=\frac{{\sout{15}}^5}{{\sout{4}}^1}\cdot \frac{{\sout{4}}^1}{{\sout{3}}^1}=5$

 

$d)7\left(x+2\right)-x=5\left(x-2\right)$

$7x+14-x=5x-10\mid -14$

$6x=5x-24\mid -5x$

$x=-24$

 

$e)-\left(x-2\right)+3\left(x-1\right)+2=0$

$-x+2+3x-3+2=0$

$2x+1=0\mid -1$

$2x=-1\mid :2$

$x=-\frac{1}{2}$

 

$f)2\left(x+\frac{1}{2}\right)-\frac{2}{3}\left(3-6x\right)=x+2$

$2x+1-\frac{2}{\sout{3}}\cdot \sout{3}-\frac{2}{{\sout{3}}^1}\cdot \left(-{\sout{6}}^{2}x\right)=x+2$

$2x+1-2+4x=x+2$

$6x-1=x+2\mid -x$

$6x-1=2\mid +1$

$5x=3\mid :5$

$x=\frac{3}{5}$

 

$g)5x-6\left(x+7\right)=8x-9\left(10+x\right)$

$5x-6x-42=8x-90-9x$

$-x-42=-x-90\mid +x$

$-42\ne -90$

Równanie jest sprzeczne.

$h)0,1\left(x-10\right)-0,6x=1,5x-4$

$0,1x-1-0,6x=1,5x-4$

$-0,5x-1=1,5x-4\mid -1,5x$

$-2x-1=-4\mid +1$

$-2x=-3\mid :\left(-2\right)$

$x=\frac{3}{2}=1\frac{1}{2}$