Matematyka

Autorzy:Wojciech Babiański, Lech Chańko, Dorota Ponczek

Wydawnictwo:Nowa Era

Rok wydania:2015

Oblicz 4.14 gwiazdek na podstawie 7 opinii
  1. Liceum
  2. 1 Klasa
  3. Matematyka

`a)\ (1 4/5-3 2/7)* 5 5/13=` `(1 28/35-3 10/35)*70/13=` 

`\ \ \ =-(3 10/35-1 28/35)*70/13=` `-(2 45/35-1 28/35)*70/13=` 

`\ \ \ =-1 17/35*70/13=` `-52/strike35^1*strike70^2/13=` `-strike52^4*2/strike13^1=-8` 

 

 

`b)\ 1 4/5-3 2/7*5 5/13=` `1 4/5-23/strike7^1*strike70^10/13=` `1 4/5-230/13=` 

`\ \ \ =1 4/5-17 9/13=` `1 52/65-17 45/65=` `-(17 45/65-1 52/65)=` 

`\ \ \ =-(16 110/65-1 52/65)=` `-15 58/65` 

 

 

`c)\ (0,4+1 2/3)*(-2)^2=` `(4/10+1 2/3)*4=` `(2/5+1 2/3)*4=` 

`\ \ \ =(6/15+1 10/15)*4=` `1 16/15*4=2 1/15*4=` `8 4/15` 

 

 

`ul(ul("uwaga:"))`   

`(-2)^2=(-2)*(-2)=4` 

`(-2^2)=-2^2=(-1)*2^2=(-1)*2*2=-4` 

 

 

`d)\ (2 3/4-3,5)*(-2^2)=`  `(2 3/4-3 1/2)*(-4)=` 

`\ \ \ =(2 3/4-3 2/4)*(-4)=` `-(3 2/4-2 3/4)*(-4)=` 

`\ \ \ =-(2 6/4-2 3/4)*(-4)=` `-3/4*(-4)=3` 

 

 

`e)\ (2 1/4+(-1/2)^2)^2=` `(2 1/4+1/4)^2=` `(2 2/4)^2=(2 1/2)^2=` 

`\ \ \ =(5/2)^2=25/4=6 1/4` 

 

 

`f)\ (0,75-(-3/4)^2)^2=` `(3/4-9/16)^2=` `(12/16-9/16)^2=` 

` \ \ \ =(3/16)^2=9/256`