Matematyka

Autorzy:Wojciech Babiański, Lech Chańko, Dorota Ponczek

Wydawnictwo:Nowa Era

Rok wydania:2015

Oblicz wartości ułamków x, y, z 4.43 gwiazdek na podstawie 7 opinii
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`a)` 

`x=1/(1+1/1)=1/(1+1)=1/2` 

 

`y=1/(1+1/(1+1/1))=` `1/(1+1/(1+1))=` `1/(1+1/2)=` `1/(1 1/2)=1/(3/2)=1:3/2=1*2/3=2/3` 

 

`z=1/(1+1/(1+1/(1+1/1)))=` `1/(1+1/(1+1/(1+1)))=` `1/(1+1/(1+1/2))=` `1/(1+1/(1 1/2))=` `1/(1+1/(3/2))=` 

`\ \ \ =1/(1+2/3)=1/(1 2/3)=1/(5/3)=1:5/3=1*3/5=3/5` 

 

 

`b)` 

`x=1+1/(2+1/2)=` `1+1/(2 1/2)=` `1+1/(5/2)=` `1+2/5=1 2/5` 

 

`y=1+1/(2+1/(2+1/2))=` `1+1/(2+1/(2 1/2))=` `1+1/(2+1/(5/2))=` `1+1/(2+2/5)=` 

`\ \ \ =1+1/(2 2/5)=` `1+1/(12/5)=1+5/12=1 5/12` 

 

`z=1+1/(2+1/(2+1/(2+1/2)))=` `1+1/(2+1/(2+1/(2 1/2)))=` `1+1/(2+1/(2+1/(5/2)))=` 

`\ \ \ =1+1/(2+1/(2+2/5))=` `1+1/(2+1/(2 2/5))=` `1+1/(2+1/(12/5))=` 

`\ \ \ =1+1/(2+5/12)=` `1+1/(2 5/12)=` `1+1/(29/12)=1+12/29=1 12/29`