I gimnazjum

Policzmy to razem 1

a) −(21​x2+21​y2−1)=−21​x2−21​y2+1 &nbsp; &nbsp; b) −(−2,5a+4,2b2−3)=

a) 5x+(7x2−9x+6)= &nbsp; 5x​+7x2−9x​+6=

a) (5x−6)+(3x−2)−(6x−7)= &nbsp; 5x−6+3x−2−6x+7= &nbsp; 2x−1 &nbsp; &nbsp; b) (6x2y−x2)+(8x2−9x2y)=

a) s1​+s2​−s3​= &nbsp; (−2x+1)+(−3x2+2x−2)−(4x2−5x+3)= &nbsp;    =−2x+1−3x2+2x−2−4x2+5x−3=

s1​=−2x+1 &nbsp; s2​=x−2 &nbsp; s3​=s2​+s1​=x−2+(−2x+1)=

−(3x2+9x+6)−[11x−(x2+9x−4)]=

a) (3x−2)−[(4x+9)−(3x−2)]= &nbsp; 3x−2−[4x+9−3x+2]= &nbsp;    =3x−2−[x+11]= &nbsp; 3x−2−x−11= &nbsp; 2x−13 &nbsp; b) x−[x+(x−1)]−[x−(x+1)]=