$d_{\max }=d_0+\Delta s$

$d_{\max }=d_0+\frac{{\left(v_F-v_{0P}\right)}^2}{2a}$

$\Delta s=\frac{{\left(v_F-v_{0P}\right)}^2}{2a}$

$d_{\max }=40\mathrm{m}+\frac{{\left(35\frac{\mathrm{m}}{\mathrm{s}}-20\frac{\mathrm{m}}{\mathrm{s}}\right)}^2}{2\cdot 6\frac{\mathrm{m}}{{\mathrm{s}}^2}}=40\mathrm{m}+\frac{{\left(15\frac{\mathrm{m}}{\mathrm{s}}\right)}^2}{12\frac{\mathrm{m}}{{\mathrm{s}}^2}}=$

$=40\mathrm{m}+\frac{225\frac{{\mathrm{m}}^{\cancel{2}}}{\cancel{{\mathrm{s}}^2}}}{12\frac{\cancel{\mathrm{m}}}{\cancel{{\mathrm{s}}^2}}}=40\mathrm{m}+18,75\mathrm{m}=58,75\mathrm{m}$