Autorzy:Praca zbiorowa

Wydawnictwo:ZamKor

Rok wydania:2015

Oblicz zawartość procentową tlenu... 4.5 gwiazdek na podstawie 6 opinii
  1. Gimnazjum
  2. 1 Klasa
  3. Chemia

 tlenek azotu(V): `N_2O_5`

`m_(N_2O_5)=2*m_N+5*m_O=2*14u+5*16u=108u `

`%O=(m_O)/(m_(N_2O_5))*100%=(5*16u)/(108u)*100%=(80u)/(108u)*100%=74,1% `

tlenek chromu(VI): `CrO_3`

`m_(CrO_3)=m_(Cr)+3*m_O=52u+3*16u=100u `

`%O=(m_O)/(m_(CrO_3))*100%=(3*16u)/(100u)*100%=(48u)/(100u)*100%=48% `

tlenek selenu(IV): `SeO_2`

`m_(SeO_2)=m_(Se)+2*m_O=79u+2*16u=111u `

`%O=(m_O)/(m_(SeO_2))*100%=(2*16u)/(111u)*100%=(32u)/(111u)*100%=28,8% `

tlenek arsenu(III): `As_2O_3`

`m_(As_2O_3)=2*m_(As)+3*m_O=2*75u+3*16u=198u `

`%O=(m_O)/(m_(As_2O_3))*100%=(3*16u)/(198u)*100%=(48u)/(198u)*100%=24,2% `

tlenek glinu: `Al_2O_3`

`m_(Al_2O_3)=2*m_(Al)+3*m_O=2*27u+3*16u=102u `

`%O=(m_O)/(m_(Al_2O_3))*100%=(3*16u)/(102u)*100%=(48u)/(102u)*100%=47,1% `