II gimnazjum

Matematyka wokół nas 2

a) &nbsp; (a+1)(a−1)=a2+a−a−1 b) &nbsp; (x−15)(x−1)=x2−x−15x+15

a) &nbsp; (5<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​)−(5<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​+3<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​)=5+15<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​−15<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​−3=2 b)

A. &nbsp; xy+3y−2x−6=y(x+3)−2(x+3)=(x+3)(y−2) &nbsp; &nbsp; IV.​

a) &nbsp; (x−2y)(x+2y)=x2−4y2=−(2y−x)(2y+x)=x2−4y2 b)

a) &nbsp; P=(3x−1)(6x+2)+(6x+3)(3x+1)= (3⋅2−1)(6⋅2+2)+(6⋅2+3)(3⋅2+1) &nbsp; =5⋅14+15⋅7=70+105=175 &nbsp;

a) Pierwsze pole: P=a⋅b=ab Pole po powiększeniu: P=(a+2)(b+2)=ab+2a+2b+4

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