$f\left(-1\right)=\sqrt{-1+2}=\sqrt{1}=1$

 

$f\left(0\right)=\sqrt{0+2}=\sqrt{2}$

 

$f\left(0,25\right)=\sqrt{0,25+2}=\sqrt{2,25}=\sqrt{2\frac{1}{4}}=\sqrt{\frac{9}{4}}=\frac{3}{2}=1\frac{1}{2}$

 

$f\left(2\right)=\sqrt{2+2}=\sqrt{4}=2$

 

$f\left(7\right)=\sqrt{7+2}=\sqrt{9}=3$

 

 

$x$	$-1$	$0$	$0,25$	$2$	$7$
$f\left(x\right)$	$1$	$\sqrt{2}$	$1\frac{1}{2}$	$2$	$3$