a) $\frac{2}{6}+h=\frac{5}{6}$

$\frac{5}{6}-\frac{2}{6}=\frac{3}{6}=\frac{1}{2}$

b) $2-1\frac{3}{8}=\frac{5}{8}$

a= $\frac{5}{8}$

c) $5-\frac{3}{4}=4\frac{1}{4}$

b= $4\frac{1}{4}$

d) $5-3\frac{3}{5}=1\frac{1}{4}$

d= $1\frac{1}{4}$

e) $5-2\frac{2}{3}=2\frac{1}{3}$

c= $2\frac{1}{3}$

f) $5\frac{1}{2}-4\frac{1}{2}=1$

p= $1$