I gimnazjum

Matematyka z plusem 1. Podręcznik

a) 5x2−15x=5x⋅x+5x⋅(−3)=5x(x−3) b) 3by−6b=3b⋅y+3b⋅(−2)=3b(y−2)

a) 33x+12​=33⋅x+3⋅4​=33(x+4)​=x+4

a) 28⋅17−28⋅15=28⋅(17−15)=28⋅2=56 b) 134⋅135−133⋅135=135⋅(134−133)=135

a) 6xy−12x2y2+24x2y=2⋅3xy+2⋅(−6x2y2)+2⋅12x2y=2(3xy−6x2y2+12x2y)

<img style="vertical-align: middle;" src="../../../math/formula?%5Cdisplaystyle%7Ba%7D%7B%5C)%7D%5C%20%7BO%7D%7Bb%7D%7Bw%7D%3D%7B8%7D%7Bc%7D-%7B4%7D%7Bd%7D%3D%7B4%7D%5Ccdot%7B2%7D%7Bc%7D-%7B4%7D%5Ccdot%7Bd%7D%3D%7B4%7D%5Ccdot%7B%5Cleft(%7B2%7D%7Bc%7D-%7Bd%7D%5Cright)%7D"> długość boku: 2c-d b) 2a3+a2=a2⋅2a+a2⋅1=a2⋅(2a+1)

P1​=21​ax P2​=21​a(x+z)−21​ax=21​ax+21​az−21​ax=21​az

a) 2x+1=2⋅ <img style="vertical-align: bottom;" src="https://prod.odrabiamy-assets.pl/uploads/content_image/image/158095/0dymLZLc9L/gbJ0Fpidpnw%3D%3D_4db29143f66b3d0a7084c0b87cc4d2f6f90844847fd2aff21c909ffd5cea66f0.jpg" width="28" height="21"> 2(x+21​)=2⋅ <img style="vertical-align: middle;" src="https://prod.odrabiamy-assets.pl/uploads/content_image/image/158095/0dymLZLc9L/gbJ0Fpidpnw%3D%3D_4db29143f66b3d0a7084c0b87cc4d2f6f90844847fd2aff21c909ffd5cea66f0.jpg" width="28" height="21"> <img style="vertical-align: middle;" src="https://prod.odrabiamy-assets.pl/uploads/content_image/image/158095/0dymLZLc9L/gbJ0Fpidpnw%3D%3D_4db29143f66b3d0a7084c0b87cc4d2f6f90844847fd2aff21c909ffd5cea66f0.jpg" width="28" height="21"> =x+21​

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