III gimnazjum

Matematyka z plusem 3

10000−5000=5000  zł (tyle pieniędzy zostanie nam po wydrukowaniu 1000 książek)

Rozwiązanie 1

Obliczamy, ile godzin w ciągu doby przesypia kot:  24⋅4825​=225​

a)0,52⋅0,54=0,52+4=0,56 b)(−2)16:(−2)8=(−2)16−8=(−2)8=28

a)3⋅1011⋅2⋅106=3⋅2⋅1011+6=6⋅1017

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jedna milionowa to  10000001​=1000000−1=(106)−1=106⋅(−1)=10−6

a)4530​=1510​=32​=32​⋅100%=3200​%=6632​%  , więc Wiesia otrzymała ocenę 3