III gimnazjum

Matematyka z plusem 3

−331​=−310​ Liczba przeciwna to 331​  , liczba odwrotna to  −103​=−0,3

Rozwiązanie 1

0,2=102​=51​ 0,35=10035​=207​

b=−0,(79)=−0,7979797…

9,51​=9510​   8,99,6​=8996​

a=512​=252​=2104​=2,4

a)−4⋅(281​)=−4⋅817​=−217​=−821​ b)−371​:11=−722​:11=−722​⋅111​=−72​

a)132​8​=8:132​=8:35​=8⋅53​=524​=454​

a)1169​<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='2.48em' viewBox='0 0 400000 2592' preserveAspectRatio='xMinYMin slice'><path d='M424,2478
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c-8,0,-12,-0.7,-12,-2z M1001 80
h400000v40h-400000z'/></svg>​⋅(−2)2+1,2⋅125​=1625​<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='2.48em' viewBox='0 0 400000 2592' preserveAspectRatio='xMinYMin slice'><path d='M424,2478
c-1.3,-0.7,-38.5,-172,-111.5,-514c-73,-342,-109.8,-513.3,-110.5,-514
c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5,25c-5.7,9.3,-9.8,16,-12.5,20
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s209,968,209,968c0,-2,84.7,-361.7,254,-1079c169.3,-717.3,254.7,-1077.7,256,-1081
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h400000v40h-400000z'/></svg>​⋅(−2)⋅(−2)+1012​⋅125​=45​⋅4+105​=5+105​=5105​=5,5

a)1000⋅2,8625=2862,5

51​

a)1 000 000 dni - ile to lat? 1000000:365≈2740 2740&gt;2014