III gimnazjum

Matematyka z plusem 3

W czworokącie suma miar kątów wynosi 360° a) trapez: suma miar kątów leżących przy tym samym ramieniu dowolnego trapezu jest równa 180° α=180o−65o=115o β=180o−80o=100o

Rozwiązanie 1

równoległobok ABCD: Kąt przy wierzchołku B: 360−90−90−70=110o Kąt przy wierzchołku C: 180−110=70o Kąt przy wierzchołku A: 70o Kąt przy wierzhołku D: 110o Romb EFGH:

a) domek: P=Pp​+Pt​−Pp1​=5⋅3+21​⋅7⋅3−2⋅1=15+10,5−2=23,5

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