II gimnazjum

Matematyka z plusem 2

cena talerza głębokiego (w złotych): g cena talerza płaskiego: p zł t gr=p+0,01t zł cena n kompletów złożonych z tuzina zestawów obiadowych (talerz głęboki+płaski): n⋅12⋅(g+p+0,01t)=12gn+12np+0,12nt <section class="answer"><h4 class="answer-heading">Odpowiedź:</h4>Za n takich kompletów trzeba zapłacić 12gn+12np+0,12nt złotych. </section>

Rozwiązanie 1

3n+2+3n=3n⋅32+3n⋅1=3n⋅(32+1)=3n⋅(9+1)=3n⋅10​

Liczby a, b, c, d można zapisać korzystając z informacji w ramce na stronie 80.  a=5k+1    b=5l+2

a) (x+7)(2x−1)=2x2−x+14x−7=2x2+13x−7   b) (2a−1)(a+4)=2a2+8a−a−4=2a2+7a−4

a) (x+5<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0 -0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​)(x−5<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0 -0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​)=x2−5<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0 -0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​2=x2−5

a) (n−2)⋅(n−2+1)=(n−2)⋅(n−1)=n2−2n−n+2=n2−3n+2

a) (m+n)(m−2)+(m−n)(m+1)=m2+mn−2m−2n+m2−mn+m−n=2m2−m−3n

a) n2(n−1)(n2+1)=n2(n3−n2+n−1)=n5−n4+n3−n2

a) Figura składa się z dwóch trójkątów: P=21​⋅(2+x+2)⋅(3+x)+21​⋅(2+x+2)⋅(3+x)=2⋅21​⋅(4+x)⋅(3+x)=(4+x)(3+x)=12+4x+3x+x2=x2+7x+12

Najwygodniejszy sposób nauki z edukacyjnym Odrabiamy AI

16

Matematyka z plusem 2