II gimnazjum

Matematyka z plusem 2

<img src="https://prod.odrabiamy-assets.pl/uploads/content_image/image/28501/JxBPis0/Cs5flqOvMLwTXQ%3D%3D_a5a3b0c31939b0448cc16b8e53ee7327c34a0eea1629ed990296ddbf1f78fb77.jpg" width="345" height="215"> a) Wymiary pudełka: x, 10-2x, 20-2x V=x(10−2x)(20−2x)=(10x−2x2)(20−2x)=200x−20x2−40x2+4x3=4x3−60x2+200x

Rozwiązanie 1

a) L=x(x+2)+1=x2+2x+1

&lt;spanclass=AMedit&gt;A. (x+3)(x2−1)=x(x2−1)+3(x2−1)=x3−x+3x2−3=x3−3s&lt;​pan&gt;

a) (x−6)(x+8)−2(x−25)=x2−6x+8x−48−2x+50=x2+2x+2

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