II gimnazjum

Matematyka z plusem 2

a) liczba ścian: 7 
liczba krawędzi: 15

Rozwiązanie 1

a) liczba krawędzi: 21  3n=21   <img style="vertical-align: middle;" src="../../../math/formula?%5Cdisplaystyle%7Bn%7D%3D%7B7%7D"> liczba ściana bocznych - n: 9  n=9=7

suma długości krawędzi: 336  krawędź podstawy: a  krawędź boczna: a + 2  12a+6(a+2)=336

Skala 1:100 czyli 1 cm odpowiada 1 m    Wysokość 2,5 m  Obliczenia:  Sufit:  P=(2,5m⋅4m)−(1,5m⋅1m)=10m2−1,5v=8,5m2

Pole powierzchni bocznej jest takie same dla obu figur. Należy więc porównać pole podstawy a - bok podstawy Kwadrat :  Pk​=a2

Pp​=21​⋅8⋅8=32   H=8

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