Wiemy, że współczynnik kierunkowy prostej wyraża się wzorem

$a=\text{tg}\alpha$

 

 

$\text{a) }\text{tg}\alpha =0,6$  

$\alpha \approx {31}^{\circ }$  

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$\text{b) }\text{tg}\alpha =-2,6$  

$\text{tg}\left({180}^{\circ }-\alpha \right)=2,6$  

${180}^{\circ }-\alpha \approx {69}^{\circ }$  

$\alpha \approx {111}^{\circ }$  

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$\text{c) }\text{tg}\alpha =9$  

$\alpha \approx {84}^{\circ }$  

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$\text{d) }\text{tg}\alpha =-14$  

$\text{tg}\left({180}^{\circ }-\alpha \right)=14$  

${180}^{\circ }-\alpha \approx {86}^{\circ }$  

$\alpha \approx {94}^{\circ }$  

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$\text{e) }\text{tg}\alpha =0,06$  

$\alpha \approx 3^{\circ }$  

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$\text{f) }\text{tg}\alpha =-0,1$  

$\text{tg}\left({180}^{\circ }-\alpha \right)=0,1$  

${180}^{\circ }-\alpha \approx 6^{\circ }$  

$\alpha \approx {174}^{\circ }$