a)

$\frac{2\frac{1}{6}}{1\frac{4}{9}}=2\frac{1}{6}:1\frac{4}{9}=\frac{13}{6}:\frac{13}{9}=\frac{13}{6}\cdot \frac{9}{13}=\frac{3}{2}=1\frac{1}{2}$

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b)

$\frac{\frac{1}{2}+\frac{1}{3}}{\frac{1}{2}}=\frac{\frac{3}{6}+\frac{2}{6}}{\frac{1}{2}}=\frac{5}{6}:\frac{1}{2}=\frac{5}{6}\cdot 2=\frac{5}{3}=1\frac{2}{3}$ 

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c)

$\frac{1\frac{5}{12}}{\frac{1}{2}-\frac{1}{3}}=\frac{1\frac{5}{12}}{\frac{3}{6}-\frac{2}{6}}=1\frac{5}{12}:\frac{1}{6}=\frac{17}{12}\cdot 6=\frac{17}{2}=8\frac{1}{2}$  

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d)

$\frac{2-\frac{1}{3}}{2-\frac{1}{2}}=\frac{1\frac{2}{3}}{1\frac{1}{2}}=\frac{\frac{5}{3}}{\frac{3}{2}}=\frac{5}{3}:\frac{3}{2}=\frac{5}{3}\cdot \frac{2}{3}=\frac{10}{9}=1\frac{1}{9}$

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e)

$\frac{\frac{3}{4}+\frac{1}{8}}{\frac{3}{4}-\frac{1}{8}}=\frac{\frac{6}{8}+\frac{1}{8}}{\frac{6}{8}-\frac{1}{8}}=\frac{\frac{7}{8}}{\frac{5}{8}}=\frac{7}{8}:\frac{5}{8}=\frac{7}{8}\cdot \frac{8}{5}=\frac{7}{5}=1\frac{2}{5}$  

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f)

$\frac{\frac{1}{2}-\frac{2}{5}}{\frac{1}{2}-1\frac{1}{5}}=\frac{\frac{5}{10}-\frac{4}{10}}{\frac{5}{10}-\frac{12}{10}}=\frac{\frac{1}{10}}{-\frac{7}{10}}=\frac{1}{10}\cdot \left(-\frac{10}{7}\right)=-\frac{1}{7}$

Uwaga! 

Odpowiedź z tyłu książki do tego podpunktu jest błędna. 

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g)

$\frac{2\frac{1}{4}-3\frac{1}{2}}{\frac{1}{8}+\frac{1}{2}}=\frac{\frac{9}{4}-\frac{7}{2}}{\frac{1}{8}+\frac{4}{8}}=\frac{\frac{9}{4}-\frac{14}{4}}{\frac{5}{8}}=-\frac{5}{4}\cdot \frac{8}{5}=-2$

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h)

$\frac{3\frac{1}{2}-2\cdot \frac{3}{4}}{2\frac{1}{2}\cdot \frac{2}{5}-2}=\frac{3\frac{1}{2}-\frac{3}{2}}{\frac{5}{2}\cdot \frac{2}{5}-2}=\frac{3\frac{1}{2}-1\frac{1}{2}}{1-2}=\frac{2}{-1}=-2$