Wykonajmy obliczenia.

$\left(7-5\frac{2}{5}\right)\cdot \frac{1}{4}=\left(6\frac{5}{5}-5\frac{2}{5}\right)\cdot \frac{1}{4}=1\frac{3}{5}\cdot \frac{1}{4}=\frac{{\cancel{8}}^2}{5}\cdot \frac{1}{{\cancel{4}}_1}=\frac{2}{5}$

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$\left(\frac{7}{9}-\frac{47}{72}\right):1\frac{1}{4}=\left(\frac{56}{72}-\frac{47}{72}\right):\frac{5}{4}=\frac{9}{72}\cdot \frac{4}{5}=\frac{1}{{\cancel{8}}_2}\cdot \frac{{\cancel{4}}^1}{5}=\frac{1}{10}$

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$6\cdot {\left(1\frac{1}{3}\right)}^2=6\cdot {\left(\frac{4}{3}\right)}^2={\cancel{6}}^2\cdot \frac{16}{{\cancel{9}}_3}=\frac{32}{3}=10\frac{2}{3}$

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${\left(\frac{5}{7}\right)}^2:\frac{5}{7}=\frac{{\cancel{25}}^5}{{\cancel{49}}_7}\cdot \frac{{\cancel{7}}^1}{{\cancel{5}}_1}=\frac{5}{7}$

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${\left(\frac{1}{3}-\frac{1}{4}\right)}^2={\left(\frac{4}{12}-\frac{3}{12}\right)}^2={\left(\frac{1}{12}\right)}^2=\frac{1}{12}\cdot \frac{1}{12}=\frac{1}{144}$

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${\left(\frac{2}{5}\right)}^2+4\frac{1}{2}\cdot 2\frac{2}{3}=\frac{4}{25}+\frac{{\cancel{9}}^3}{{\cancel{2}}_1}\cdot \frac{{\cancel{8}}^4}{{\cancel{3}}_1}=\frac{4}{25}+12=12\frac{4}{25}$

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$5\cdot {\left(\frac{1}{2}\right)}^2+15\cdot {\left(\frac{1}{3}\right)}^2=5\cdot \frac{1}{4}+{\cancel{15}}^5\cdot \frac{1}{{\cancel{9}}_3}=\frac{5}{4}+\frac{5}{3}=\frac{15}{12}+\frac{20}{12}=\frac{35}{12}=2\frac{11}{12}$

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$\frac{1}{9}-{\left(\frac{5}{6}-\frac{2}{3}\right)}^2=\frac{1}{9}-{\left(\frac{5}{6}-\frac{4}{6}\right)}^2=\frac{1}{9}-{\left(\frac{1}{6}\right)}^2=\frac{1}{9}-\frac{1}{36}=\frac{4}{36}-\frac{1}{36}=\frac{3}{36}=\frac{1}{12}$

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Zakreślmy  podane wyniki w tabeli:

$\frac{1}{144}$

$\frac{2}{85}$

$\frac{1}{12}$

$\frac{1}{10}$

$\frac{1}{9}$

$\frac{2}{5}$

$\frac{5}{7}$

$\frac{5}{6}$

$1\frac{3}{5}$

$2\frac{1}{7}$

$2\frac{11}{12}$

$5\frac{8}{11}$

$10\frac{2}{3}$

$12\frac{4}{25}$

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Hasło: DROMADER

(jest to wielbłąd jednogarbny)