Uzupełniamy:

$2,33-2,12=\boxed{0,21}\left(\text{bo}2\frac{33}{100}-2\frac{12}{100}=\frac{21}{100}\right)$

$7,48-4,23=\boxed{3,25}\left(\text{bo}7\frac{48}{100}-4\frac{23}{100}=3\frac{25}{100}\right)$

$2-0,1=\boxed{1,9}\left(\text{bo}2-\frac{1}{10}=1\frac{10}{10}-\frac{1}{10}=1\frac{9}{10}\right)$

$3,1-0,3=\boxed{2,8}\left(\text{bo}3\frac{1}{10}-\frac{3}{10}=2\frac{11}{10}-\frac{3}{10}=2\frac{8}{10}\right)$

Uzupełniamy:

$4,1-0,9=\boxed{3,2}\left(\text{bo}4\frac{1}{10}-\frac{9}{10}=3\frac{11}{10}-\frac{9}{10}=3\frac{2}{10}\right)$

$\underset{2,20}{\underbrace{2,2}}-0,09=\boxed{2,11}\left(\text{bo}2\frac{20}{100}-\frac{9}{100}=2\frac{11}{100}\right)$

$2,2-0,1=\boxed{2,1}\left(\text{bo}2\frac{2}{10}-\frac{1}{10}=2\frac{1}{10}\right)$

$\underset{2,20}{\underbrace{2,2}}-0,19=\boxed{2,01}\left(\text{bo}2\frac{20}{100}-\frac{19}{100}=2\frac{1}{100}\right)$

$3,2-2,4=\boxed{0,8}\left(\text{bo}3\frac{2}{10}-2\frac{4}{10}=2\frac{12}{10}-2\frac{4}{10}=\frac{8}{10}\right)$

Uzupełniamy:

$4,37-3,17=\underset{1,2}{\underbrace{\boxed{1,20}}}\left(\text{bo}4\frac{37}{100}-3\frac{17}{100}=1\frac{20}{100}\right)$

$5-1,98=\boxed{3,02}\left(\text{bo}5-1\frac{98}{100}=4\frac{100}{100}-1\frac{98}{100}=3\frac{2}{100}\right)$

$6-2,81=\boxed{3,19}\left(\text{bo}6-2\frac{81}{100}=5\frac{100}{100}-2\frac{81}{100}=3\frac{19}{100}\right)$

$\underset{1,20}{\underbrace{1,2}}-1,17=\boxed{0,03}\left(\text{bo}1\frac{20}{100}-1\frac{17}{100}=\frac{3}{100}\right)$

$\underset{1,50}{\underbrace{1,5}}-0,05=\boxed{1,45}\left(\text{bo}1\frac{50}{100}-\frac{5}{100}=1\frac{45}{100}\right)$

Rysunek: