Przypomnimy informacje dotyczące kuli.

 

Uzupełniamy tabelę.

	$\left(1\right)$	$\left(2\right)$	$\left(3\right)$
$V$	$\frac{2}{3}\pi {\mathbf{r}}^3$	$\frac{1}{6}\pi {\mathbf{r}}^3$	$\frac{1}{2}\pi {\mathbf{r}}^3$
$P$	$3\pi {\mathbf{r}}^2$	$\frac{5}{4}\pi {\mathbf{r}}^2$	$\frac{11}{4}\pi {\mathbf{r}}^2$

 

Obliczenia:

• 2 wiersz

$\left(1\right)V=\frac{1}{2}\cdot \frac{4}{3}\pi r^3=\frac{2}{3}\pi r^3$  

$\left(2\right)V=\frac{1}{8}\cdot \frac{4}{3}\pi r^3=\frac{1}{6}\pi r^3$  

$\left(3\right)V=\frac{3}{8}\cdot \frac{4}{3}\pi r^3=\frac{1}{2}\pi r^3$  

• 3 wiersz

$\left(1\right)P=\frac{1}{2}\cdot 4\pi r^2+\pi r^2=2\pi r^2+\pi r^2=3\pi r^2$  

$\left(2\right)P=\frac{1}{8}\cdot 4\pi r^2+3\cdot \frac{1}{4}\cdot \pi r^2=\frac{1}{2}\pi r^2+\frac{3}{4}\pi r^2=\frac{2}{4}\pi r^2+\frac{3}{4}\pi r^2=\frac{5}{4}\pi r^2$  

$\left(3\right)P=\frac{3}{8}\cdot 4\pi r^2+5\cdot \frac{1}{4}\cdot \pi r^2=\frac{3}{2}\pi r^2+\frac{5}{4}\pi r^2=\frac{6}{4}\pi r^2+\frac{5}{4}\pi r^2=\frac{11}{4}\pi r^2$