$\{\begin{array}{l}{x}^2+y^2={\left(x+2\right)}^2+{\left(y+1\right)}^2+1\\ 2\sqrt{5}x-\sqrt{5}y=-\sqrt{5}\mid :\sqrt{5}\end{array}$  

 

$\{\begin{array}{l}{x}^2+y^2=x^2+4x+4+y^2+2y+1+1\\ 2x-y=-1\end{array}$  

 

$\{\begin{array}{l}-2y=4x+6\mid :\left(-2\right)\\ -y=-2x-1\end{array}$   

 

$\{\begin{array}{l}y=-2x-3\\ -y=-2x-1\end{array}$  

Dodajmy stronami oba równania:

$y-y=-2x-3-2x-1$  

$4x=-4\mid :4$  

$x=-1$  

 

Podstawmy x do jednego z równań:

$y=-2\cdot \left(-1\right)-3=2-3=-1$  

 

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Rozwiązanie graficzne:

$\{\begin{array}{l}y=-2x-3\\ y=2x+1\end{array}$  

 

$\mathbf{x}$	$0$	$-2$
$\mathbf{y}=-2\mathbf{x}-3$	$-3$	$-2\cdot \left(-2\right)-3=4-3=1$
$\mathbf{y}=2\mathbf{x}+1$	$1$	$2\cdot \left(-2\right)+1=-4+1=-3$

     

$\{\begin{array}{l}x=-1\\ y=-1\end{array}$