$p=9^{-\frac{3}{4}}={\left(3^2\right)}^{-\frac{3}{4}}=3^{2\cdot \left(-\frac{3}{4}\right)}=3^{-\frac{3}{2}}$  

 

A.

$p={\left(\sqrt{3}\right)}^{\frac{1}{3}}={\left(3^{\frac{1}{2}}\right)}^{\frac{1}{3}}=3^{\frac{1}{2}\cdot \frac{1}{3}}=3^{\frac{1}{6}}\ne 3^{-\frac{3}{2}}$  

Zdanie fałszywe.

 

B.

$p=\frac{\sqrt{3}}{9}=\frac{3^{\frac{1}{2}}}{3^2}=3^{\frac{1}{2}-2}=3^{-\frac{3}{2}}$  

Zdanie prawdziwe.

 

C.

${\left({\left(\sqrt{3}\right)}^{\sqrt{3}}\right)}^{-\sqrt{3}}={\left(\sqrt{3}\right)}^{\sqrt{3}\cdot \left(-\sqrt{3}\right)}={\left(3^{\frac{1}{2}}\right)}^{-3}=3^{\frac{1}{2}\cdot \left(-3\right)}=3^{-\frac{3}{2}}$  

Zdanie prawdziwe.