a)

$\frac{\frac{17}{40}-0,2}{1\frac{3}{5}}=\frac{\frac{17}{40}-\frac{2}{10}}{\frac{8}{5}}=\frac{\frac{17}{40}-\frac{8}{40}}{\frac{8}{5}}=\frac{\frac{9}{40}}{\frac{8}{5}}=\frac{9}{40}:\frac{8}{5}=\frac{9}{{\sout{40}}^8}\cdot \frac{{\sout{5}}^1}{8}=\frac{9}{64}$  

b)

$\frac{\left(3\frac{3}{5}-2\right)\cdot 5}{0,04}=\frac{1\frac{3}{5}\cdot 5}{0,04}=\frac{\frac{8}{{\sout{5}}^1}\cdot {\sout{5}}^1}{0,04}=8:0,04=800:4=200$