a) (3​+1)3=(3​)3+3⋅(3​)2⋅1+3⋅3​⋅12+13=
   =33​+3⋅3⋅1+3⋅3​⋅1+1=33​+9+33​+1=63​+10
b) (2​−1)3=(2​)3−3⋅(2​)2⋅1+3⋅2​⋅12−13=
   =22​−3⋅2⋅1+3⋅2​⋅1−1=22​−6+32​−1=52​−7
c) (22​+3​)3=(22​)3+3⋅(22​)2⋅3​+3⋅22​⋅(3​)2+(3​)3=
   =23⋅(2​)3+3⋅22⋅(2​)2⋅3​+62​⋅3+33​=
   =8⋅22​+3⋅4⋅2⋅3​+182​+33​=162​+243​+182​+33​=
   =273​+342​
d) (5​−23​)3=(5​)3−3⋅(5​)2⋅23​+3⋅5​⋅(23​)2−(23​)3=
   =55​−3⋅5⋅23​+3⋅5​⋅22⋅(3​)2−23⋅(3​)3=
   =55​−303​+3⋅5​⋅4⋅3−8⋅33​=
   =55​−303​+365​−243​=415​−543​
Oceń to zadanie:
Åšrednia:
4.60
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