Uzupełniamy luki, korzystając z tabeli podanej na poprzedniej stronie.

a)

$\sin {213}^{\circ }=\sin \left({180}^{\circ }+{33}^{\circ }\right)=-\sin {33}^{\circ }$  

$\cos {260}^{\circ }=\cos \left({180}^{\circ }+{80}^{\circ }\right)=-\cos {80}^{\circ }$  

$\text{tg}{1250}^{\circ }=\text{tg}\left(3\cdot {360}^{\circ }+{170}^{\circ }\right)=\text{tg}{170}^{\circ }=\text{tg}\left({180}^{\circ }-{10}^{\circ }\right)=-\text{tg}{10}^{\circ }$  

$\text{ctg}{231}^{\circ }=\text{ctg}\left({180}^{\circ }+{51}^{\circ }\right)=+\text{ctg}{51}^{\circ }$  

---

b)

$\sin {181}^{\circ }=\sin \left({270}^{\circ }-{89}^{\circ }\right)=-\cos {89}^{\circ }$  

$\cos {201}^{\circ }=\cos \left({270}^{\circ }-{69}^{\circ }\right)=-\sin {69}^{\circ }$  

$\text{tg}{1259}^{\circ }=\text{tg}\left(3\cdot {360}^{\circ }+{179}^{\circ }\right)=\text{tg}{179}^{\circ }=\text{tg}\left({90}^{\circ }+{89}^{\circ }\right)=-\text{ctg}{89}^{\circ }$  

$\text{ctg}{261}^{\circ }=\text{ctg}\left({270}^{\circ }-9^{\circ }\right)=+\text{tg}{9}^{\circ }$  

---

c)

$\sin {285}^{\circ }=\sin \left({270}^{\circ }+{15}^{\circ }\right)=-\cos {15}^{\circ }$  

$\cos {301}^{\circ }=\cos \left({270}^{\circ }+{31}^{\circ }\right)=+\sin {31}^{\circ }$  

$\text{tg}{328}^{\circ }=\text{tg}\left({270}^{\circ }+{58}^{\circ }\right)=-\text{ctg}{58}^{\circ }$  

$\text{ctg}{349}^{\circ }=\text{ctg}\left({270}^{\circ }+{79}^{\circ }\right)=-\text{tg}{79}^{\circ }$  

---

d)

$\sin {293}^{\circ }=\sin \left({360}^{\circ }-{67}^{\circ }\right)=-\sin {67}^{\circ }$  

$\cos {311}^{\circ }=\cos \left({360}^{\circ }-{49}^{\circ }\right)=+\cos {49}^{\circ }$  

$\text{tg}{1338}^{\circ }=\text{tg}\left(3\cdot {360}^{\circ }+{258}^{\circ }\right)=\text{tg}{258}^{\circ }=\text{tg}\left({180}^{\circ }+{78}^{\circ }\right)=+\text{tg}{78}^{\circ }$  

$\text{ctg}{336}^{\circ }=\text{ctg}\left({360}^{\circ }-{24}^{\circ }\right)=-\text{ctg}{24}^{\circ }$  

---

Uwaga! W książce podano błędną odpowiedź do ostatniego przykładu z podpunktu b).