III gimnazjum

Matematyka z plusem 3. Zbiór zadań 2001

Pole powierzchni walca obliczamy ze wzoru: Pc​=Pp​+Pb​ czyli Pc​=2πr2+2πrH a) Pc​=2⋅32π+2π⋅3⋅7=18π+42π=60π

Pole powierzchni bocznej walca można obliczyć ze wzoru: Pb​=2πrH gdzie r to promień podstawy a H wysokość walca. Promień walca wynosi 3cm a wysokość 10 cm, π

Objętość stożka obliczymy ze wzoru: V=31​πr2⋅H czyli a) V=31​⋅π52⋅6=50π b) wysokość stożka obliczymy z trójkąta 30,60,90stopni H=a3<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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