$\text{a)}-\frac{4}{5}\cdot 3\frac{3}{4}+4,5:\left(-1,5\right)=-\frac{{\sout{4}}^1}{{\sout{5}}^1}\cdot \frac{{\sout{15}}^3}{{\sout{4}}^1}+\left(-3\right)=-1\cdot 3-3=-3-3=-6$  

$\text{b)}\left(-1\frac{1}{6}\right)\cdot \left(-\frac{2}{7}\right)+\frac{12,4}{-37,2}=\frac{{\sout{7}}^1}{{\sout{6}}^3}\cdot \frac{{\sout{2}}^1}{{\sout{7}}^1}-\frac{{\sout{124}}^1}{{\sout{372}}^3}=\frac{1}{3}-\frac{1}{3}=0$  

$\text{c)}-12,84:\left(-4\right)-13\frac{1}{2}:\left(-27\right)=3,21+\frac{{\sout{27}}^1}{2}\cdot \frac{1}{{\sout{27}}^1}=3,21+\frac{1}{2}=3,21+0,5=3,71$  

$\text{d)}-\frac{1,2}{0,6}+\frac{4,8}{0,8}-\frac{12,66}{2,11}=-\frac{12}{6}+\frac{48}{8}-\frac{1266}{211}=-2+6-6=-2$  

$\text{e)}1,6\cdot \left(-\frac{5}{8}\right)+\left(-2,4\right):0,12+41=-1\frac{3}{5}\cdot \frac{5}{8}-240:12+41=$  

$=-\frac{{\sout{8}}^1}{{\sout{5}}^1}\cdot \frac{{\sout{5}}^1}{{\sout{8}}^1}-20+41=-1-20+41=20$  

$\text{f)}\left(-3,6:0,09\right):\left(-5\right)+\left(-1,4\right):0,7=360:9:5+\left(-14:7\right)=-40:\left(-5\right)+\left(-2\right)=$  

$=8-2=6$