8 szkoły podstawowej

Matematyka. Kalendarz ósmoklasisty

Obliczamy ile wynosi objętość dużego sześcianu o krawędzi długości 1 m.  1 m=100 cm   Zatem:

Rozkładamy liczbę 450 000 na czynniki pierwsze.

Każdą z podanych liczb zapisujemy w jak najprostszej postaci. Podstawa każdej z potęg musi wynosić 3.  A. 334−333=333⋅3−333=333(3−1)=333⋅2 &gt; 333

Obliczamy wartość każdego z podanych wyrażeń.  A. 614⋅63619​=614+3619​=617619​=619−17=62

Kwadrat ABCD ma pole 2 razy większe od pola kwadratu EFGH.  PABCD​=2⋅PEFGH​   Bok kwadratu ABCD ma długość 6.

Podaną liczbę zapisujemy w jak najprostszej postaci wykonując odpowiednie działania na pierwiastkach.

Liczbę 5√180 zapisujemy tak, aby pod pierwiastkiem znajdowała się liczba 5.  Wykorzystujemy do tego odpowiednie własności działań na pierwiastkach.

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