$3\frac{2}{5}=\underline{\frac{17}{5}},\text{bo}\underline{3\cdot 5+2=15+2=17}$  

$10\frac{4}{9}=\underline{\frac{94}{9}},\text{bo}\underline{10\cdot 9+4=90+4=94}$  

$5\frac{1}{3}=\underline{\frac{16}{3}},\text{bo}\underline{5\cdot 3+1=15+1=16}$  

$7\frac{1}{4}=\underline{\frac{29}{4}},\text{bo}\underline{7\cdot 4+1=28+1=29}$