$\frac{4,5-\frac{1}{6}}{4,5+\frac{1}{6}}=\frac{\frac{45}{10}-\frac{1}{6}}{\frac{45}{10}+\frac{1}{6}}=\frac{\frac{135}{30}-\frac{5}{30}}{\frac{135}{30}+\frac{5}{30}}=\frac{\frac{130}{30}}{\frac{140}{30}}=\frac{130}{30}\cdot \frac{30}{140}=\frac{{\sout{130}}^{13}}{{\sout{30}}^1}\cdot \frac{{\sout{30}}^1}{{\sout{140}}^{14}}=\frac{13}{1}\cdot \frac{1}{14}=\frac{13}{14}$  

$\frac{4,5}{4\frac{2}{3}}-\frac{\frac{1}{6}}{4,\left(6\right)}=\frac{\frac{45}{10}}{\frac{14}{3}}-\frac{\frac{1}{6}}{\frac{14}{3}}=\frac{45}{10}\cdot \frac{3}{14}-\frac{1}{6}\cdot \frac{3}{14}=\frac{9}{2}\cdot \frac{3}{14}-\frac{1}{{\sout{6}}^2}\cdot \frac{{\sout{3}}^1}{14}=\frac{27}{28}-\frac{1}{2}\cdot \frac{1}{14}=\frac{27}{28}-\frac{1}{28}=\frac{26}{28}=\frac{13}{14}$  

 

$\frac{3}{14}\cdot \left(4,5-\frac{1}{6}\right)=\frac{3}{14}\cdot \left(\frac{45}{10}-\frac{1}{6}\right)=\frac{3}{14}\cdot \left(\frac{9}{2}-\frac{1}{6}\right)=\frac{3}{14}\cdot \left(\frac{27}{6}-\frac{1}{6}\right)=\frac{3}{14}\cdot \frac{26}{6}=\frac{{\sout{3}}^1}{{\sout{14}}^7}\cdot \frac{{\sout{26}}^{13}}{{\sout{6}}^2}=\frac{1}{7}\cdot \frac{13}{2}=\frac{13}{14}$  

 

$\frac{\frac{1}{6}-4,5}{\frac{1}{6}+4,5}=\frac{\frac{1}{6}-\frac{45}{10}}{\frac{1}{6}+\frac{45}{10}}=\frac{\frac{5}{30}-\frac{135}{30}}{\frac{5}{30}+\frac{135}{30}}=\frac{-\frac{130}{30}}{\frac{140}{30}}=-\frac{130}{30}\cdot \frac{30}{140}=-\frac{{\sout{130}}^{13}}{{\sout{300}}^1}\cdot \frac{{\sout{30}}^1}{{\sout{140}}^{14}}=-\frac{13}{1}\cdot \frac{1}{14}=-\frac{13}{14}$  

 

Odp.: D