Obliczmy najpierw ile wynoszą liczby x i y.

$x={3,6}^5\cdot {\left(\frac{5}{9}\right)}^5:4^5={\left(3,6\cdot \frac{5}{9}:4\right)}^5={\left(\frac{36}{10}\cdot \frac{5}{9}\cdot \frac{1}{4}\right)}^5={\left(\frac{{\sout{36}}^4}{10}\cdot \frac{5}{{\sout{9}}^1}\cdot \frac{1}{4}\right)}^5={\left(\frac{4}{10}\cdot \frac{5}{1}\cdot \frac{1}{4}\right)}^5={\left(\frac{{\sout{4}}^1}{10}\cdot \frac{5}{1}\cdot \frac{1}{{\sout{4}}^1}\right)}^5={\left(\frac{1}{10}\cdot \frac{5}{1}\cdot \frac{1}{1}\right)}^5={\left(\frac{5}{10}\right)}^5={\left(\frac{1}{2}\right)}^5=\frac{1}{32}$

$y=\frac{7^9}{{15}^9}\cdot {\left(2\frac{1}{7}\right)}^9={\left(\frac{7}{15}\cdot 2\frac{1}{7}\right)}^9={\left(\frac{7}{15}\cdot \frac{15}{7}\right)}^9=1^9=1$  

Obliczmy sumę tych liczb.

$x+y=\frac{1}{32}+1=1\frac{1}{32}$  

Odp. Suma tych liczb to $1\frac{1}{32}$