Rysunek poglądowy:

$\mathrm{tg}{80}^o=\frac{8}{x}$  

$x=\frac{8}{\mathrm{tg}{80}^o}\approx \frac{8}{5,6713}\approx 1,41$  

 

$\mathrm{tg}{50}^o=\frac{8}{y}$  

$y=\frac{8}{\mathrm{tg}{50}^o}\approx \frac{8}{1,1918}\approx 6,71$  

 

Pole trapezu:

$P=\frac{\left|AD\right|+\left|EF\right|}{2}\cdot h=\frac{1,41+11+6,71+11}{2}\cdot 8=4\cdot 30,12\approx 120,5\left[{\text{cm}}^2\right]$