$a)\left(\sqrt{2\frac{1}{4}}-\sqrt{\frac{9}{16}}\right)\cdot 1\frac{1}{3}:3\frac{1}{3}=\left(\sqrt{\frac{9}{4}}-\frac{3}{4}\right)\cdot \frac{4}{3}:\frac{10}{3}=\left(\frac{3}{2}-\frac{3}{4}\right)\cdot \frac{4}{3}:\frac{10}{3}=$  

$=\left(\frac{6}{4}-\frac{3}{4}\right)\cdot \frac{4}{3}:\frac{10}{3}=\frac{{\sout{3}}^1}{{\sout{4}}^1}\cdot \frac{{\sout{4}}^1}{{\sout{3}}^1}:\frac{10}{3}=1:\frac{10}{3}=1\cdot \frac{3}{10}=\frac{3}{10}$  

$b)4\frac{1}{2}:\left(\sqrt{\frac{4}{9}}-\sqrt{\frac{1}{16}}\right):1\frac{4}{5}=\frac{9}{2}:\left(\frac{2}{3}-\frac{1}{4}\right):\frac{9}{5}=\frac{9}{2}:\left(\frac{8}{12}-\frac{3}{12}\right):\frac{9}{5}=\frac{9}{2}:\frac{5}{12}:\frac{9}{5}=$ $b)4\frac{1}{2}:\left(\sqrt{\frac{4}{9}}-\sqrt{\frac{1}{16}}\right):1\frac{4}{5}=\frac{9}{2}:\left(\frac{2}{3}-\frac{1}{4}\right):\frac{9}{5}=\frac{9}{2}:\left(\frac{8}{12}-\frac{3}{12}\right):\frac{9}{5}=\frac{9}{2}:\frac{5}{12}:\frac{9}{5}=$  

$=\frac{{\sout{9}}^1}{{\sout{2}}^1}\cdot \frac{{\sout{12}}^6}{{\sout{5}}^1}\cdot \frac{{\sout{5}}^1}{{\sout{9}}^1}=6$  

$c)\sqrt{1\frac{7}{9}}:\left(2\frac{1}{4}-1\frac{5}{6}\right):\sqrt{7\frac{1}{9}}=\sqrt{\frac{16}{9}}:\left(\frac{9}{4}-\frac{11}{6}\right):\sqrt{\frac{64}{9}}=\frac{4}{3}:\left(\frac{27}{12}-\frac{22}{12}\right):\frac{8}{3}=$  

$=\frac{4}{3}:\frac{5}{12}:\frac{8}{3}=\frac{{\sout{4}}^1}{{\sout{3}}^1}\cdot \frac{12}{5}\cdot \frac{{\sout{3}}^1}{{\sout{8}}^2}=\frac{12}{10}=\frac{6}{5}=1\frac{1}{5}$  

$d)\left(\sqrt{9}-\sqrt{0,09}\right):\sqrt{0,01}=\left(3-0,3\right):0,1=2,7:0,1=27$  

$e)\left(\frac{\sqrt{16}}{5}-2,8\right)\cdot \sqrt{0,81}=\left(\frac{4}{5}-2,8\right)\cdot 0,9=\left(0,8-2,8\right)\cdot 0,9=-2\cdot 0,9=-1,8$  

$f)\left(\frac{\sqrt{36}}{4}-1,8\right)\cdot \frac{2}{\sqrt{25}}=\left(\frac{6}{4}-1,8\right)\cdot \frac{2}{5}=\left(\frac{3}{2}-1,8\right)\cdot \frac{2}{5}=\left(1,5-1,8\right)\cdot 0,4=-0,3\cdot 0,4=-0,12$  

$g)\frac{\sqrt{2\frac{7}{9}}-\sqrt{2\frac{1}{4}}}{\sqrt{1\frac{9}{16}}:\sqrt{1\frac{11}{25}}}=\frac{\sqrt{\frac{25}{9}}-\sqrt{\frac{9}{4}}}{\sqrt{\frac{25}{16}}:\sqrt{\frac{36}{25}}}=\frac{\frac{5}{3}-\frac{3}{2}}{\frac{5}{4}:\frac{6}{5}}=\frac{\frac{10}{6}-\frac{9}{6}}{\frac{5}{4}\cdot \frac{5}{6}}=\frac{\frac{1}{6}}{\frac{25}{24}}=\frac{1}{{\sout{6}}^1}\cdot \frac{{\sout{24}}^4}{25}=\frac{4}{25}$  

$h)\frac{\sqrt{\frac{1}{16}}-\sqrt{6\frac{1}{4}}}{\sqrt{1\frac{19}{81}}-\sqrt{\frac{1}{9}}}=\frac{\frac{1}{4}-\sqrt{\frac{25}{4}}}{\sqrt{\frac{100}{81}}-\frac{1}{3}}=\frac{\frac{1}{4}-\frac{5}{2}}{\frac{10}{9}-\frac{1}{3}}=\frac{\frac{1}{4}-\frac{10}{4}}{\frac{10}{9}-\frac{3}{9}}=\frac{-\frac{9}{4}}{\frac{7}{9}}=\left(-\frac{9}{4}\right)\cdot \left(\frac{9}{7}\right)=-\frac{81}{28}$    

$i)\frac{\sqrt{3,7-3,06}}{\sqrt{0,25}-\sqrt{100}}=\frac{\sqrt{0,64}}{0,5-10}=\frac{0,8}{-9,5}=\frac{8}{-95}=-\frac{8}{95}$