$\frac{\left(2^{\frac{4}{3}}+{81}^{\frac{2}{3}}\right)\cdot \left(4\sqrt[3]{4}-18\sqrt[3]{18}+81\cdot {\left(9^2\right)}^{\frac{1}{3}}\right)-{\left({\left(-2\right)}^{-8}\right)}^{-\frac{1}{2}}}{{\left(\sqrt{3}\right)}^{12}}=$

  $=\frac{\left(2^{\frac{4}{3}}+{\left(3^4\right)}^{\frac{2}{3}}\right)\cdot \left(4^1\cdot 4^{\frac{1}{3}}-{18}^1\cdot {18}^{\frac{1}{3}}+9^2\cdot 9^{\frac{2}{3}}\right)-{\left(-2\right)}^4}{{\left(3^{\frac{1}{2}}\right)}^{12}}=$  

$=\frac{\left(2^{\frac{4}{3}}+3^{\frac{8}{3}}\right)\cdot \left(4^{1\frac{1}{3}}-{18}^{1\frac{1}{3}}+9^{2\frac{2}{3}}\right)-2^4}{3^6}=$