2 szkoły ponadpodstawowej

II liceum

II technikum

MATeMAtyka 2. Zakres podstawowy. Po gimnazjum

Rozwiązanie 1

<img src="https://prod.odrabiamy-assets.pl/uploads/content_image/image/43985/r957XjaalBySj%2B0cJL8R6A%3D%3D_1c6ed5f261cbc64cf778f77d065372f14c14970cb36e38462fe5f27045918d22.png" width="371" height="282"> Obliczamy odległość |AS|, czyli promień okręgu, a następnie L, czyli długość okręgu.   a) r=∣AS∣=(2−(−4))2+(3−1)2<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.88em' viewBox='0 0 400000 1944' preserveAspectRatio='xMinYMin slice'><path d='M983 90
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M834 80h400000v40h-400000z'/></svg>​=4⋅10<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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Okręgi są styczne zewnętrznie jeśli odległość pomiędzy ich środkami jest równa sumie długości ich promieni: ∣S1​S2​∣=r1​+r2​ Obliczmy odległość pomiędzy ich środkami:

Najwygodniejszy sposób nauki z edukacyjnym Odrabiamy AI

Ćwiczenie 4

MATeMAtyka 2. Zakres podstawowy. Po gimnazjum